3x^2-15x-600=0

Solution for 3x^2-15x-600=0 equation:

3x^2-15x-600=0

a = 3; b = -15; c = -600;
Δ = b2-4ac
Δ = -152-4·3·(-600)
Δ = 7425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7425}=\sqrt{225*33}=\sqrt{225}*\sqrt{33}=15\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15\sqrt{33}}{2*3}=\frac{15-15\sqrt{33}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15\sqrt{33}}{2*3}=\frac{15+15\sqrt{33}}{6}
$